1. Impedance estimates
You recall the common approximations for how to deal with inductors and capacitors at DC and also very large frequencies.[1]
\(f\) | \(\!\rightarrow\! 0\) | \( \!\rightarrow\! \infty\) |
---|---|---|
Zinductor = \(sL\) |
short |
open |
Zcapacitor = \(\dfrac{1}{sC}\) |
open |
short |
Look at each of the four places in Table 1 and think about what each one means and where (in frequency) it is located. See in your mind’s eye a wire representing a short-circuit and a nothing for the open-circuit, like in Figure 1.
Replacing a device with an open- or short-circuit usually makes the simplified circuit easy to analyze.
2. First-order circuits
Figure 2 shows R·C and R·L circuits in all possible series-shunt configurations.[2]
Which circuit(s) have out shorted to in at DC? (Refer to them like graph quadrants)
Quadrant I
Which circuit(s) have out shorted to the lower node at DC?
Quadrant IV
Which circuit(s) shorts out to in at very large frequencies?
Quadrant III
Which circuit(s) blocks very high frequencies from appearing at out by short-circuiting out to the lower node?
Quadrant II
Which circuits are appropriately named low-pass filters?
Quadrants I and II
Which circuits are appropriately named high-cut filters?
Trick question! Also quadrants I and II. Sometimes circuits for audio applications use this terminology.
Which circuits should be called high-pass filters?
Quadrants III and IV
The time constants for these circuits are \(\tau = RC\) and \(\tau = L/R\), corresponding to special frequencies (−3 dB frequencies here) of \(\frac{1}{2\pi RC}\) and \(\frac{1}{2\pi\, \left. ^L \!/\! _R \right.}\), respectively. Remember that the −3 dB point is where the output magnitude is 3 dB lower than the “flat” portion of the response.
3. Second-order circuits
3.1. First example
Consider operation at DC or very low frequencies:
-
The series inductor becomes a -circuit.
-
while the shunt capacitor becomes a -circuit.
-
Therefore, low frequencies (do | do not)[4] pass through this filter.
What about very high frequencies?
-
The series inductor becomes a -circuit.
-
while the shunt capacitor becomes a -circuit.
-
Therefore, high frequencies (do | do not) pass through this filter.
Do you notice how the passing or blocking of signals is double-reinforced with the arrangement of open- and short-circuits?
What is an appropriate name for a filter of this behavior?
“low-pass or high-cut filter”
3.2. Second example
Describe what happens at DC or low frequencies. Finish your mental description before revealing!
Describe what happens at high frequencies.
Because the low’s get cut off, this is a low-cut filter.
Because the high’s pass through, this is a high-pass filter.
…same thing.
3.3. Parallel LC
We most frequently deal with the relationship between V and I for an element by its impedance (V/I), but here it is easier to deal with admittance.
Parallel elements have an equivalent impedance of \(Z_{eq} = \left( \dfrac{1}{Z_1} + \dfrac{1}{Z_2} \right)^{-1}\) and an equivalent admittance of simply \(Y_{eq} = Y_1 + Y_2\). If you remember the impedances of reactive elements, the admittances are simply their recipricals:[5]
\(Y_C = j\omega C\) and \(Y_L = \dfrac{-j}{\omega L}\)
So, an L-C in parallel has an admittance of \(Y_{L\parallel C}=j\omega C - \dfrac{j}{\omega L}\).
Both low and high frequencies yield a short-circuit at the output node to 0 V, so this is neither a low-pass nor a high-pass filter. What happens at middle frequencies?
Look back carefully at \(Y_{L\parallel C}\) and notice that the term can be zero if ω is the right value.
What value of ω makes \(Y_{L\parallel C}\) ? Do the algebra yourself first!
\(w_0 = \pm \dfrac{1}{\sqrt{LC}}\)
Remember that admittance is \(\frac{I}{V}\) and a value of zero would mean that zero current flows no matter the voltage difference. This is simply the description of an open-circuit.
So, at some middle frequency, the parallel LC behaves like an open-circuit, allowing the input signal to pass through the circuit at full-scale.
Now your turn. Use what you know to sketch the frequency response of this filter.
3.4. Series LC
Use what you know to sketch the frequency response of the following two RLC circuits.
Will you use impedance or admittance to find the LC series equivalent value?
impedance, of course, because Z's add in series.
What happens at the special frequency?
Elsie is a program from Tonne Software that designs, analyzes, and plots lumped-element (L-C) filters. Combine engineers' tendency to name things plainly with a dry sense of humor and this is what you get :) |